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Exam Code: 1z0-061
Exam Name: Oracle Database 12c: SQL Fundamentals
One year free update, No help, Full refund!
1z0-061 Exam Cram Total Q&A: 75 Questions and Answers
Last Update: 01-11,2016

1z0-061 Dumps PDF Detail: 1z0-061 Exam Cram

Exam Code: 1z0-420
Exam Name: Oracle Fusion HCM: Talent Management 2014 Essentials
One year free update, No help, Full refund!
1z0-420 Practice Exam Total Q&A: 79 Questions and Answers
Last Update: 01-11,2016

1z0-420 Exam Questions Detail: 1z0-420 Practice Exam

NO.1 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. Fourth normal form
B. Second normal form
C. First normal form
D. Third normal form
Answer: B

1z0-061 test answers   

NO.2 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Both statements 1 and 2 execute successfully and give different results.
B. Only statement 1 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give the same required result.
D. Only statement 2 executes successfully and gives the required result.
Answer: C

1z0-061 Study Materials   

NO.3 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-c, 2-a, 3-b, and 4-d
B. 1-d, 2-b, 3-a, and 4-c
C. 1-a, 2-b, 3-c, and 4-d
D. 1-c, 2-d, 3-a, and 4-b
Answer: A

1z0-061 Real Questions   

NO.4 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Substituting a character string in a text expression with a specified string
B. Finding the number of characters in an expression
C. Combining more than two columns or expressions into a single column in the output
D. Displaying a date in a nondefault format
Answer: A,B,D

1z0-061 Free Demo   

NO.5 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. RIGHT OUTER JOIN; LEFT OUTER JOIN
B. JOIN; JOIN
C. LEFT OUTER JOIN; RIGHT OUTER JOIN
D. FULL OUTER JOIN; FULL OUTER JOIN
Answer: A

1z0-061 Study Guide   

NO.6 In the customers table, the CUST_CITY column contains the value 'Paris' for the
CUST_FIRST_NAME 'Abigail'.
Evaluate the following query:
What would be the outcome?
A. Abigail Pa
B. An error message
C. Abigail IS
D. Abigail PA
Answer: A

1z0-061 exam dumps   1z0-061 Training online   

NO.7 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
D. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
Answer: C

1z0-061 Practice Test   

NO.8 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It produces an error because the AMT_SPENT column contains a null value.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: A

1z0-061 PDF VCE   
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.

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