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Latest Oracle 1Z0-803 of exam practice questions and answers

Java SE 7 Programmer I

Exam Number: 1Z0-803 / 1Z0-803

Duration: 120 minutes

Associated Certifications: Oracle Certified Associate, Java SE 7 Programmer

Number of Questions: 70

Exam Product Version: Java SE,

Passing Score: 63%

Exam Price: US$ 150

Validated Against:

This exam has been validated against SE 7.

format: Multiple Choice

 

Recommended Training

Exam Preparation Seminar

Practice Exams

 

TOPICS

Java Basics

Working With Java Data Types

Using Operators and Decision Constructs  

Creating and Using Arrays

Using Loop Constructs

Working with Methods and Encapsulation

Working with Inheritance

Handling Exceptions



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1Z0-803 Exam PrepExam Code: 1Z0-803
Exam Name: Java SE 7 Programmer I
One year free update, No help, Full refund!
1Z0-803 Test Answers Total Q&A: 216 Questions and Answers
Last Update: 03-11,2015

1Z0-803 Exam Dumps Detail : Click Here

 

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NO.1 View the exhibit:
public class Student {
public String name = "";
public int age = 0;
public String major = "Undeclared";
public boolean fulltime = true;
public void display() {
System.out.println("Name: " + name + " Major: " + major); }
public boolean isFullTime() {
return fulltime;
}
}
Which line of code initializes a student instance?
A. Student student1;
B. Student student1 = Student.new();
C. Student student1 = new Student();
D. Student student1 = Student();
Answer: C

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NO.2 Given:
Why will the code not compile?
A. A static field cannot be private.
B. The getLetter method has no body.
C. There is no setLetter method.
D. The letter field is uninitialized.
E. It contains a method named Main instead of ma
Answer: B

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Explanation:
The getLetter() method needs a body public static int getLetter() { }; .

NO.3 Given:
What is the result?
A. Compilation fails
B. An exception is thrown at runtime
C. There is no result because this is not correct way to determine the hash code
D. Hash is: 111111, 44444444, 999999999
Answer: A

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Explanation:
The compilation fails as SampleClassA and SampleClassB cannot override SampleClass because the
return type of SampleClass is int, while the return type of SampleClassA and SampleClassB is long.
Note: If all three classes had the same return type the output would be: Hash is : 111111, 44444444,
999999999

NO.4 Given:
public class ColorTest {
public static void main(String[] args) {
String[] colors = {"red", "blue","green","yellow","maroon","cyan"};
int count = 0;
for (String c : colors) {
if (count >= 4) {
break;
}
else {
continue;
}
if (c.length() >= 4) {
colors[count] = c.substring(0,3);
}
count++;
}
System.out.println(colors[count]);
}
}
What is the result?
A. Yellow
B. Maroon
C. Compilation fails
D. A StringIndexOutOfBoundsException is thrown at runtime.
Answer: C

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Explanation:
The line,if (c.length() >= 4) {, is never reached. This causes a compilation error.
Note:The continue statement skips the current iteration of a for, while , or do-while loop.
An unlabeled break statement terminates the innermost switch, for, while, or do-while statement,
but a labeled break terminates an outer statement.

NO.5 public class ForTest {
public static void main(String[] args) {
int[] arrar = {1,2,3};
for ( foo ) {
} } }
Which three are valid replacements for foo so that the program will compiled and run?
A. int i: array
B. int i = 0; i < 1; i++
C. ;;
D. ; i < 1; i++
E. ; i < 1;
Answer: A,B,C

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NO.6 Given:
public class ComputeSum {
public int x;
public int y;
public int sum;
public ComputeSum (int nx, int ny) {
x = nx; y =ny;
updateSum();
}
public void setX(int nx) { x = nx; updateSum();}
public void setY(int ny) { x = ny; updateSum();}
void updateSum() { sum = x + y;}
}
This class needs to protect an invariant on the sum field.
Which three members must have the private access modifier to ensure that this invariant is
maintained?
A. The x field
B. The y field
C. The sum field
D. The ComputerSum ( ) constructor
E. The setX ( ) method
F. The setY ( ) method
Answer: C,E,F

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Explanation:
The sum field and the two methods (setX and SetY) that updates the sum field.

NO.7 Given: Which two declarations will compile?
A. int a, b, c = 0;
B. int a, b, c;
C. int g, int h, int i = 0;
D. int d, e, F;
E. int k, l, m; = 0;
Answer: A,D

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NO.8 Given the code fragment:
Int [] [] array = {{0}, {0, 1}, {0, 2, 4}, {0, 3, 6, 9}, {0, 4, 8, 12, 16}};
Systemout.printIn(array [4] [1]);
System.out.printIn (array) [1] [4]);
What is the result?
A. 4 Null
B. Null 4
C. An IllegalArgumentException is thrown at run time
D. 4 An ArrayIndexOutOfBoundException is thrown at run time
Answer: D

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Explanation:
The first println statement, System.out.println(array [4][1]);, works fine. It selects the element/array
with index 4, {0, 4, 8, 12, 16}, and from this array it selects the element with index 1, 4. Output: 4 The
second println statement, System.out.println(array) [1][4]);, fails. It selects the array/element with
index 1, {0, 1}, and from this array it try to select the element with index 4. This causes an exception.
Output: 4
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 4

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Posted 2015/3/12 15:45:04  |  Category: Oracle  |  Tag: 1Z0-803 BootcampOracle